To get random bytes from a file at 23 different positions, you can use Delphi’s TFileStream in combination with the Random function. Here’s an example:
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unit Unit1; interface uses Windows, Classes, SysUtils; procedure ReadRandomBytes(const fileName: string; numPoints: Integer); implementation procedure ReadRandomBytes(const fileName: string; numPoints: Integer); var FileStream: TFileStream; FileSize: Int64; Position: Int64; Buffer: Byte; i: Integer; begin try // Open the file in read-only mode FileStream := TFileStream.Create(fileName, fmOpenRead or fmShareDenyNone); try // Get the size of the file FileSize := FileStream.Size; // Check if there are enough bytes in the file if FileSize < numPoints then begin Writeln(‘Error: File size is less than the requested number of points.’); Exit; end; // Set the random seed based on the current time Randomize; // Read a random byte at 23 different positions for i := 1 to numPoints do begin // Generate a random position within the file size Position := Random(FileSize); // Set the file stream position FileStream.Position := Position; // Read a single byte from the file FileStream.ReadBuffer(Buffer, SizeOf(Buffer)); // Process the random byte as needed Writeln(Format(‘Random Byte %d at Position %d: %d’, [i, Position, Buffer])); end; finally // Close the file stream FileStream.Free; end; except on E: Exception do Writeln(‘Error: ‘ + E.Message); end; end; end. |
You can call this procedure by providing the path to the file and the number of points:
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begin ReadRandomBytes(‘C:\Path\To\Your\File.bin’, 23); end. |
This example uses Random to generate random positions within the file and reads a single byte at each random position. Adjust the code according to your specific requirements.
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