Solving pool problems in delphi

Here is a function in Delphi that you can use to solve pool problems:

function SolvePoolProblem(volume: Double; length: Double; width: Double; depth: Double): Double;
var
  surfaceArea: Double;
begin
  // Calculate the surface area of the pool
  surfaceArea := length * width + (length * depth * 2) + (width * depth * 2);

  // Calculate the volume of water needed to fill the pool
  Result := volume * surfaceArea;
end;

function SolvePoolProblem(volume: Double; length: Double; width: Double; depth: Double): Double;

var

surfaceArea: Double;

begin

// Calculate the surface area of the pool

surfaceArea := length * width + (length * depth * 2) + (width * depth * 2);

// Calculate the volume of water needed to fill the pool

Result := volume * surfaceArea;

end;

This function takes in four parameters:

volume: The volume of water needed to fill the pool (in liters)
length: The length of the pool (in meters)
width: The width of the pool (in meters)
depth: The depth of the pool (in meters)

It returns the volume of water needed to fill the pool, based on the surface area of the pool.

To use this function, you would call it like this:

neededVolume := SolvePoolProblem(1000, 10, 5, 2);

1	neededVolume := SolvePoolProblem(1000, 10, 5, 2);

This would calculate the volume of water needed to fill a pool with 1000 liters of water, with a length of 10 meters, a width of 5 meters, and a depth of 2 meters. The function would return the volume of water needed to fill the pool.

Solving pool problems in delphi

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